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If a 5 kg bowling ball is lifted to a height of 2 meters, how much potential
energy does it have?


Sagot :

Answer:

Explanation:

givens

m = 5 kg

a = 9.8

h = 2 m

Formula

PE = m*g*h

Solution

PE = 5 * 9.8 * 2

PE = 98 This does not take sig digs into account. The answer would be 100 if you have to consider significant digits.