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Answer:
E = 20 N/C
Explanation:
Given that,
Charge, q = 2 C
Force experience, F = 40 N
We need to find the electric field at that location.
The electric field in terms of electric force is given by :
F = qE
Where
E is the electric field
[tex]E=\dfrac{F}{q}\\\\E=\dfrac{40\ N}{2\ C}\\E=20\ N/C[/tex]
So, the electric field at that location is 20 N/C.