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In the circle below, QS is a diameter. Suppose =mQR76° and =m∠QRT46°. Find the following.

In The Circle Below QS Is A Diameter Suppose MQR76 And MQRT46 Find The Following class=

Sagot :

Answer:

∠ RQS = 58°, ∠ SRT = 44°

Step-by-step explanation:

The angle at the centre of a circle is equal to the measure of the arc that subtends it, then

angle at centre = arc QR = 76°

∠ RQS = 180° - (76 + 46)° ← sum of angles in a triangle

∠ RQS = 180° - 122° = 58°

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∠ SRQ = 90° ( angle in a semicircle )

∠ SRT = 90° - ∠ QRT = 90° - 46° = 44°

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