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A shop keeper buys 20kg of sugar at Birr y per kg. he sells 16kgs at Birr (y+3/4) per kg and the rest at Birr (y+1) per kg. what is his profit.​

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Answer:

The profit is $16

Step-by-step explanation:

From the question, we have 20 kg at Birr y per kg

The cost price is thus;

20 * y = 20y Birr

Now for the selling price;

16 kg was sold at (y + 3/4) Birr per kg

we have here that;

16 * y + 3/4 * 16

= 16y + 12

The rest is thus; 20 - 16 = 4 kg

The rest of this at (y + 1) per kg will be

4 * (y + 1) = 4y + 4

The total selling price is thus;

4y + 4 + 16y + 12 = 20y + 16

The profit is the difference between the selling and cost price

We have this as:

20y + 16 - 20y

= $16

The profit of the shopkeeper is $16.

Given that,

A shopkeeper buys 20kg of sugar at Birr y per kg.

He sells 16kgs at Birr (y+3/4) per kg and the rest at Birr (y+1) per kg.

We have to determine,

What is his profit?

According to the question,

The total quantity of sugar he buys is 20kg at y birr y kg.

Then the cost of sugar is,

[tex]\rm = 20 \times y\\\\= 20y[/tex]

And he sells 16kgs at Birr (y+3/4) per kg and the rest at Birr (y+1) per kg.

Then, the cost of sugar he sells is,

[tex]= \rm 16(y+\dfrac{3}{4})\\\\= 16y+ 16\times \dfrac{3}{4}\\\\= 16y + 12[/tex]

Left quantity of sugar = The total quantity of sugar - quantity of sugar he sells,

Left quantity of sugar = 20 kg - 16 kg

Left quantity of sugar = 4 kg

The rest of this at (y + 1) per kg will be,

[tex]\rm = 4 \times (y + 1) \\\\= 4y + 4[/tex]

The total selling price is thus;

[tex]\rm =4y + 4 + 16y + 12 \\\\= 20y + 16[/tex]

Therefore,

The profit is the difference between the selling and cost price is,

[tex]\rm = 20y + 16 - 20y\\\\= 16[/tex]

Hence, The required profit of the shopkeeper is $16.

For more details refer to the link given below.

https://brainly.com/question/17710675

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