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17. A train is travelling at a speed of 90 km/h.
Brakes are applied, so as to produce a
uniform acceleration of -0.5 m/s2. Find how
far the train will go before it is brought to rest?
Pg 110​

Sagot :

Answer:

x = 625 m

Explanation:

To solve this exercise we use the kinematics relations

          v² = v₀² - 2 a x

indicate that the train stops therefore its final speed is zero (v = 0)

           0 = v₀² - 2a x

           x = [tex]\frac{v_o^2}{2a}[/tex]

let's slow down to the SI system

           v₀ = 90 km / h (1000 m / 1km) (1h / 3600 s) = 25 m / s

let's calculate

           x = [tex]\frac{25^2}{2 \ 0.5}[/tex]

           x = 625 m

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