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What is an equation of the line that passes through the points (−6,−2) and (−3,−3)?

Sagot :

Answer:

y = -1/3x - 4  (slope-intercept form)

or

x + 3y = -12 (Standard form).

Step-by-step explanation:

The slope of the line = (-3 - (-2)) / (-3 - (-6))

= -1 / 3.

Using the point-slope form of straight line:

y - y1 = m(x - x1) we have:

y - (-2) = -1/3(x - -6))

y + 2 = -1/3(x + 6

y + 2 = -1/3x - 2

y = -1/3x - 4

In standard form (multiplying thru by 3):

3y = -x - 12

x + 3y = -12.

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