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Answer:
[tex]Rate = -5[/tex]
Step-by-step explanation:
Given
[tex]f(x) = 2x^2 - x - 4[/tex]
[tex]-4 \le x \le 2[/tex]
Required
Determine the average slope over the given interval
This is calculated as:
[tex]Rate= \frac{f(b) - f(a)}{b - a}[/tex]
Where:
[tex]a = -4[/tex]
[tex]b =2[/tex]
So:
[tex]Rate= \frac{f(2) - f(-4)}{2 - (-4)}[/tex]
[tex]Rate= \frac{f(2) - f(-4)}{2 +4}[/tex]
[tex]Rate= \frac{f(2) - f(-4)}{6}[/tex]
Solving for f(2) and f(-4), we have:
[tex]f(x) = 2x^2 - x - 4[/tex]
[tex]f(2) = 2 *2^2 -2 - 4[/tex]
[tex]f(2) = 2[/tex]
[tex]f(-4) = 2*(-4)^2 - (-4) - 4[/tex]
[tex]f(-4) = 2*16 +4 - 4[/tex]
[tex]f(-4) = 32[/tex]
So, the equation becomes
[tex]Rate= \frac{f(2) - f(-4)}{6}[/tex]
[tex]Rate= \frac{2 - 32}{6}[/tex]
[tex]Rate= \frac{-30}{6}[/tex]
[tex]Rate = -5[/tex]