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Sagot :
Answer:
5 acres < soybeans < 495
2 acres < wheat < 198 acres
Step-by-step explanation:
If farmer plans to plant minimum of soybeans, it should be 5 acres of soybeans costing $1000. The remaining cost of $98,000 will be available for maximum of wheat, i.e., 198 acres of wheat.
Similarly, if we go for minimum possible planting for wheat, it should be 2 acres, and then resulting in 495 acres for soybeans
5 acres < soyabeans < 495
2 acres < wheat < 198 acres
Answer:
The multiplier for soybeans is 200, which is dollars per acre.
Step-by-step explanation:
5 acres ≤ soybeans ≤ 495 acres (constraint)
2 acres ≤ wheat ≤ 198 acres (constraint)
150w + 125s = 100,000
This would represent 150 acres of wheat and 125 acres of soybeans. The acres of wheat would add up to $75,000 because 150 x 500 = 75,000 and the acres of soybeans would add up to $25,000 because 125 x 200 = 25,000. (example of a solution, there are more possible)
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