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Y varies directly as X and inversely as the square of Z. Y=30 when X=75 and Z=5. Find Y when X=36 and Z=2

Sagot :

Answer:

Y  when X=36 and Z=2 is 90

Step-by-step explanation:

Given -

Y varies directly as X and inversely as the square of Z

[tex]y = \frac{kx}{z^2}\\30 = \frac{k *75}{5^2} \\30 = 75k/25[/tex]

[tex]k = 10[/tex]

As we know

[tex]y = \frac{kx}{z^2}[/tex]

Substituting value of X = 36 and Z = 2 in above equation, we get -

[tex]y = \frac{10*36}{2*2} \\y = 90[/tex]

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