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If h (x) = {(-2,3), (0,4), (1,6), (2, 9)}

then what set of values represent h-1 (x) ?

Sagot :

Answer:

[tex]h^{-1}(x)=\{(3,-2),(4,0),(6,1),(9,2)\}[/tex]

Step-by-step explanation:

Given: [tex]h(x)=\{(-2,3),(0,4),(1,6),(2,9)\}[/tex]

To find: [tex]h^{-1}(x)[/tex]

Solution:

A relation is said to be a function if each and every element of the domain has a unique image in the co-domain.

Inverse of a function exist if it is both one to one and onto.

[tex]h(x)=\{(-2,3),(0,4),(1,6),(2,9)\}[/tex]

[tex]h^{-1}(x)=\{(3,-2),(4,0),(6,1),(9,2)\}[/tex]

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