Explore IDNLearn.com's extensive Q&A database and find the answers you're looking for. Ask anything and receive well-informed answers from our community of experienced professionals.
Sagot :
Answer:
#include<stdio.h>
int main(){
unsigned char var;
int p,n;
printf("a: ");
scanf("%x",&var);
printf("p: ");
scanf("%d",&p);
printf("n: ");
scanf("%d",&n);
while(1){
char command;
scanf("%c",&command);
if(command=='S'){
var=var | (((1<<n)-1)<<(p-1));
} else if(command=='R'){
var=var & ~(((1<<n)-1)<<(p-1));
} else if(command=='F'){
var=var ^ (((1<<n)-1)<<(p-1));
} else if(command=='D'){
printf("a = %02x H : ",var);
int i;
for(i=7;i>=4;i--){
printf("%d",((1<<i)&(var))>>i);
printf(" ");
for(i=3;i>=0;i--){
printf("%d",((1<<i)&(var))>>i);
printf(" B\n");
}
}
} else if(command=='I'){
printf("a = ");
scanf("%x",&var);
}
}
}
Explanation:
The C source code gets user inputs from a keyboard as integer numbers, p and n, which is converted to binary (8 bits of one and zero value) as the memory for the input hexadecimal number and character values are also inputs from the keyboard, used as flags to determine the way the hexadecimal number is stored or displayed.
We appreciate your participation in this forum. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. Your questions are important to us at IDNLearn.com. Thanks for stopping by, and come back for more reliable solutions.
