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How much heat is released when 1.4 mol of hydrogen fluoride are produced? H2(g) +F2(g) → 2HF(g) +536kJ (Please show work)

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Maacastrobridn

Answer:

375.2 kJ

Explanation:

  • H₂(g) +F₂(g) → 2HF(g) +536kJ

The information the equation above provides lets us know that when 2 mol of hydrogen fluoride (HF) are produced, 536 kJ of energy (as heat) is produced.

We can then state a rule of three:

  • 2 mol HF --------  536 kJ
  • 1.4 mol HF --------- X

And solve for X:

  • X = 1.4 mol * 536 kJ / 2 mol
  • X = 375.2 kJ
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