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Sagot :
Answer: 0.233 M
Explanation: (0.550 M)(0.0320 L)= 17.6e-3 mol NaOH
3:1 ratio of NaOH to H3PO4 so divide the moles of NaOH (17.6e-3) by 3. You will get 5.86e-3.
Finally, divide this number (the moles of H3PO4) by the volume (0.252 L) to get 0.233 M
The concentration of given acid base reaction will be 0.226 M
What is Acid base reaction?
The chemical reactions that take place when acids and bases are combined together are known as acid-base reactions. Acids and bases are discussed in terms of hydrogen ion exchange in the Bronsted-Lowry hypothesis. A conjugate acid as well as a conjugate base are the end products of such a reaction.
The given acid base reaction is :
H3PO4 + 3NaOH = Na3PO4 + 3H2O.
It can be seen that 3 moles of NaOH give one moles of Na3PO4.
Moles of NaOH = 0.550 M/ 0.0320 L = 17.18
So, by divide the moles of NaOH = 17.18 /3 = 5.72
The given volume = 25.2 mL = 0.252 L
Concentration of acid base reaction = n / v
where, n = moles of solute , v = liters of solution.
Now, put the value of given data in above concentration of acid base reaction formula.
Concentration of acid base reaction = 5.72 / 0.252 L = 22 .69
Therefore, the concentration of acid base reaction will be 0.226M.
To know more about concentration of acid base reaction click here.
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