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How many atoms are in a 591 g sample of gold?
116,000 atoms
1.81 × 1024 atoms
3.00 atoms
3.60 × 1025 atoms

Sagot :

Eduard22slyidn

The number of atoms present in 591 g of gold is 1.81×10²⁴ atoms

Avogadro's hypothesis

From Avogadro's hypothesis,

1 mole of Gold = 6.02×10²³ atoms

But

1 mole of gold = 197 g

Thus,

197 g of gold = 6.02×10²³ atoms

How to determine the atoms in 591 g of gold

197 g of gold = 6.02×10²³ atoms

Therefore,

591 g of gold = (591 × 6.02×10²³) / 197

591 g of gold = 1.81×10²⁴ atoms

Thus, 1.81×10²⁴ atoms is present in 591 g of gold.

Learn more about Avogadro's number:

https://brainly.com/question/26141731

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