IDNLearn.com connects you with a community of experts ready to answer your questions. Explore a wide array of topics and find reliable answers from our experienced community members.
Sagot :
Answer:
the force B is less than the maximum force consequently Boat B floats
Explanation:
To solve this exercise let's use the pressure defined
P = [tex]\frac{F}{A}[/tex]
F = P A
let's start for boat A
let's search the area
A = l a
A₁ = 45 126
A₁ = 5670 m²
the force applied by this ship is
F₁ = 2300 5670
F₁ = 1.3 10⁷ N
now we do the calculation for ship B
A₂ = 6 115
A₂ = 690 m²
F₂ = P₂ A₂
F₂ = 2700 690
F₂ = 1.8 10⁶ N
indicate that the force should not be greater than F₀ = 2.0 10⁶ N, let's look for the relationship with each one
[tex]\frac{F_1}{F_0}[/tex] = 1.3 10⁷/2 10⁶
F₁ = 6.5 F₀
This force is greater than the one that can resist therefore the ship and sinks
[tex]\frac{F_2}{F_o}[/tex] = 1.8 /2
F₂ = 0.9 F₀
therefore this force is less than the maximum force consequently Boat B floats
Thank you for using this platform to share and learn. Don't hesitate to keep asking and answering. We value every contribution you make. IDNLearn.com is committed to providing accurate answers. Thanks for stopping by, and see you next time for more solutions.