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In ΔBCD, the measure of ∠D=90°, the measure of ∠C=83°, and DB= 1.3feet. What is the length of CD to the nearest tenth of a foot.

Sagot :

Snogidn

Answer:

[tex]CD\approx0.2[/tex]

Step-by-step explanation:

By the tangent ratio, [tex]tanC=\frac{DB}{CD}[/tex]. Substituting the given values into this equation gives us:

[tex]tan83[/tex]° [tex]= \frac{1.3}{CD}[/tex]

[tex]CD*tan83[/tex]° [tex]=1.3[/tex] (Multiply both sides of the equation by [tex]CD[/tex])

[tex]CD=\frac{1.3}{tan83\textdegree}[/tex] (Divide both sides of the equation by [tex]tan83\textdegree[/tex])

[tex]CD=0.15962\approx0.2[/tex]

Hope this helps!

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