Answered

IDNLearn.com provides a user-friendly platform for finding and sharing accurate answers. Get accurate and comprehensive answers from our network of experienced professionals.

A truck moving at 6.0 m/s applies the brakes and stops after skidding 12.0 m.

(a) Find the uniform deceleration. (20 pts)

(b) Find the time it takes for the truck to stop. (20 pts)

Sagot :

Cjrodriguez89idn

Answer:

a) a= -1.5 m/s²

b) t = 4.0 s

Explanation:

a)

  • Since we are told that the deceleration is uniform, we can use the following kinematic equation:

        [tex]v_{f} ^{2} - v_{o} ^{2} = 2*a*\Delta X (1)[/tex]

  • Since the truck finally stops, this means that vf = 0.
  • Replacing the values of v₀, and Δx in (1), we can solve for a, as follows:

       [tex]a =\frac{-(v_{o}^{2})}{2*\Delta X} = \frac{-(6.0m/s)^{2} }{2* 12.0m} = -1.5 m/s2 (2)[/tex]

b)

  • Since we know the value of the initial and final velocity, and the value of the acceleration also, we can apply the definition of acceleration, solving for time t, as follows:

       [tex]\Delta t = \frac{-v_{o}}{a} = \frac{-6.0m/s}{-1.5m/s2} = 4.0 s (2)[/tex]

We appreciate every question and answer you provide. Keep engaging and finding the best solutions. This community is the perfect place to learn and grow together. Your questions deserve precise answers. Thank you for visiting IDNLearn.com, and see you again soon for more helpful information.