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Answer:
[tex]\mathbf{\dfrac{2b- 1}{2b}}[/tex]
Step-by-step explanation:
[tex]\text{The given equation is:}[/tex]
[tex]\dfrac{a}{b}+ (\dfrac{1}{4} \times \dfrac{1}{b}) = \dfrac{1}{2}[/tex]
[tex]\text{To find:}[/tex]
[tex]\dfrac{1}{2} } \div {\dfrac{a}{b} }[/tex]
[tex]\text{From the given equation:}[/tex]
[tex]\dfrac{a}{b}+ (\dfrac{1}{4b}) = \dfrac{1}{2}[/tex]
[tex]\dfrac{a}{b} = \dfrac{1}{2} - (\dfrac{1}{4b})[/tex]
[tex]\dfrac{a}{b} = \dfrac{4b- 2}{(2) (4b)}[/tex]
[tex]\dfrac{a}{b} = \dfrac{4b- 2}{8b}[/tex]
[tex]\text{Now; the value of}[/tex] [tex]\dfrac{a}{b} \div \dfrac{1}{2}[/tex]
∴
[tex]\implies \dfrac{4b- 2}{8b} \div \dfrac{1}{2}[/tex]
[tex]\implies \dfrac{4b- 2}{8b} \times \dfrac{2}{1}[/tex]
[tex]\implies \dfrac{4b- 2}{4b}[/tex]
[tex]\implies \dfrac{2b- 1}{2b}[/tex]