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Calculate the pH of a solution formed by mixing 550.0 mL of 0.30 M HClO with 275.0 mL of 0.20 M CsClO. The Ka for HClO is 2.9 × 10-8.

Sagot :

Answer:

pH = 7.08

Explanation:

We can solve this problem using Henderson-Hasselbach's equation:

  • pH = pKa + log[tex]\frac{[ClO^-]}{[HClO]}[/tex]

With the given concentrations and volumes, we can calculate the new values for [ClO⁻] and [HClO] when the solutions are mixed:

  • Total volume = 550.0 mL + 275.0 mL = 825.0 mL
  • [HClO] = 550 mL * 0.30 M / 825 mL = 0.20 M
  • [ClO⁻] = 275 mL * 0.20 M / 825 mL = 0.07 M

Now we calculate pKa:

  • pKa = -log(Ka) = 7.54

Finally we calculate the pH:

  • pH = 7.54 + log[tex]\frac{0.07}{0.2}[/tex] = 7.08