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Answer:
[tex]Jane = 15\frac{3}{10}[/tex]
Step-by-step explanation:
Given
[tex]Kent = 12\frac{4}{5}[/tex]
[tex]Lane = 1\frac{1}{6} + Kent[/tex]
[tex]Jane = 1\frac{1}{3} + Lane[/tex]
Required
Determine Jane's age
Substitute [tex]Kent = 12\frac{4}{5}[/tex] in [tex]Lane = 1\frac{1}{6} + Kent[/tex]
[tex]Lane = 1\frac{1}{6} + 12\frac{4}{5}[/tex]
[tex]Lane = \frac{7}{6} + \frac{64}{5}[/tex]
Take LCM
[tex]Lane = \frac{45+384}{30}[/tex]
[tex]Lane = \frac{419}{30}[/tex]
Substitute [tex]Lane = \frac{419}{30}[/tex] in [tex]Jane = 1\frac{1}{3} + Lane[/tex]
[tex]Jane = 1\frac{1}{3} + \frac{419}{30}[/tex]
[tex]Jane = \frac{4}{3} + \frac{419}{30}[/tex]
Take LCM
[tex]Jane = \frac{40+419}{30}[/tex]
[tex]Jane = \frac{459}{30}[/tex]
[tex]Jane = 15\frac{3}{10}[/tex]