Issamehla10idn
Answered

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14
What would be the slope of equation #1 in the following system? (Graphing)
2x+3y=12
4x-3y=15
(Worth 10 points )
A:1/2
B: -1
C:3/4
D:-2/3

Sagot :

MrRoyalidn

Answer:

[tex]m = -\frac{2}{3}[/tex]

Step-by-step explanation:

Given

[tex]2x+3y=12[/tex]

[tex]4x-3y=15[/tex]

Required

Slope of #1

[tex]2x+3y=12[/tex]

Make y the subject

[tex]3y = -2x + 12[/tex]

Divide through by 3

[tex]y = -\frac{2}{3}x + \frac{12}{3}[/tex]

[tex]y = -\frac{2}{3}x + 4[/tex]

An equation has the form:

[tex]y = mx + c[/tex]

Where

[tex]m = slope[/tex]

Compare [tex]y = mx + c[/tex] and [tex]y = -\frac{2}{3}x + 4[/tex]

[tex]m = -\frac{2}{3}[/tex]

Hence, the slope is [tex]-\frac{2}{3}[/tex]

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