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Answer:
24/99
Step-by-step explanation:
From the question given above, the following data were obtained:
White (W) balls = 4
Black (B) balls = 5
Blue (Bl) balls = 2
Probability that they are of different color =?
Next, we shall determine the total number of balls in the bag. This can be obtained as follow:
White (W) balls = 4
Black (B) balls = 5
Blue (Bl) balls = 2
TOTAL = 4 + 5 + 2 = 11 balls
Next, we shall determine the possible outcome of draw. This can be obtained as follow.
The possible outcome could be:
WBLB or WBBL or BBLW or BWBL or BLBW or BLWB
Next we shall determine the probability of each of outcomes.
Since the ball is drawn without replacement, it means the total number of ball will reduce after each draw.
White (W) balls = 4
Black (B) balls = 5
Blue (Bl) balls = 2
TOTAL = 11
P(WBLB) = 4/11 × 2/10 × 5/9 = 40/990
P(WBLB) = 4/99
P(WBBL) = 4/11 × 5/10 × 2/9 = 40/990
P(WBBL) = 4/99
P(BBLW) = 5/11 × 2/10 × 4/9 = 40/990
P(BBLW) = 4/99
P(BWBL) = 5/11 × 4/10 × 2/9 = 40/990
P(BWBL) = 4/99
P(BLBW) = 2/11 × 5/10 × 4/9 = 40/990
P(BLBW) = 4/99
P(BLWB) = 2/11 × 4/10 × 5/9 = 40/990
P(BLWB) = 4/99
Finally, we shall determine the probability that they are of different color. This can be obtained as follow:
P(WBLB) = 4/99
P(WBBL) = 4/99
P(BBLW) = 4/99
P(BWBL) = 4/99
P(BLBW) = 4/99
P(BLWB) = 4/99
Probability that they are of different color =?
Probability that they are of different color = P(WBLB) + P(WBBL) + P(BBLW) + P(BWBL) + P(BLBW) + P(BLWB)
= 4/99 + 4/99 + 4/99 + 4/99 + 4/99 + 4/99
= (4 + 4 + 4 + 4 + 4 + 4)/99
= 24/99
Thus, the probability that they are of different color is 24/99