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Given that triangle ABC ~ XYZ, AB= 4,XY=3,and XZ= 5, find AC

Given That Triangle ABC XYZ AB 4XY3and XZ 5 Find AC class=

Sagot :

Answer:

[tex]AC = \frac{20}{3}[/tex]

Step-by-step explanation:

Given

[tex]AB = 4[/tex]

[tex]XY = 3[/tex]

[tex]XZ = 5[/tex]

Required

Find AC

ABC XYZ

To solve AC, we make use of the following equivalent ratios.

[tex]AB : AC = XY : XZ[/tex]

This gives:

[tex]4 : AC = 3 : 5[/tex]

Express as fraction

[tex]\frac{4 }{ AC }= \frac{3 }{ 5}[/tex]

Cross multiply

[tex]3 * AC = 4 * 5[/tex]

[tex]3 * AC = 20[/tex]

Solve for AC

[tex]AC = \frac{20}{3}[/tex]