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Answer:
Acceleration, a = 2.47 seconds
Explanation:
Given the following data;
Time, t = 1.8 seconds
Distance = 4 meters
Initial velocity = 0 m/s (since it's starting from rest)
To find the acceleration of the toy car, we would use the second equation of motion;
[tex] S = ut + \frac {1}{2}at^{2}[/tex]
Where;
S represents the displacement or height measured in meters.
u represents the initial velocity measured in meters per seconds.
t represents the time measured in seconds.
a represents acceleration measured in meters per seconds square.
Substituting into the equation, we have;
Substituting into the formula, we have;
[tex] 4 = 0(1.8) + \frac {1}{2}*a*(1.8)^{2}[/tex]
[tex] 4 = 0 + \frac {1}{2}*a*3.24[/tex]
[tex] 4 = \frac {1}{2}*a*3.24[/tex]
Cross multiplying, we have;
[tex] 8 = 3.24a[/tex]
[tex] a = \frac {8}{3.24}[/tex]
Acceleration, a = 2.47 seconds