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Which set of ordered pairs demonstrates a function?
A
(-2,-4), (-1, -2), (1, 2), (2, 4)
B
(-2, 4), (1, 2), (1, -2), (2.-4)
C
(-2,4), (-1, 2). (-1, 2), (-2,-4)
D
(-2, 4). (-1, 2), (-1, -2), (-2,-4)


Sagot :

I think it’s A because the x is in order from -1,-2, 1, 2

The set of ordered pairs from listed options demonstrating a function is given by: Option A: (-2,-4), (-1, -2), (1, 2), (2, 4)

Firstly, we need the definition a function; based on which we can distinguish the correct set of ordered pairs.

What is a function?

If we have two sets A and B as:

[tex]A = \{a_1, a_2, ... \}\\B = \{b_1, b_2, ... \}[/tex]

Then, function [tex]f: A \rightarrow B[/tex] is a connection of elements of A to B such that one element of A is connected to only single element of B, and not many.

The connected pairs are then written as:

[tex]\{(a_i_1,b_j_1), (a_i_2, b_j_2), ... \}[/tex] under the function f.

Now, for the listed ordered pairs, checking if they're functions or not:

  • Case 1: (-2,-4), (-1, -2), (1, 2), (2, 4)

Each single input is connected with single output. So it is demonstrating a function.

  • Case 2: (-2, 4), (1, 2), (1, -2), (2.-4)

In this case, 1 is connected to 2, and -2 both. Thus, it's not representing a function.

  • Case 3: (-2,4), (-1, 2), (-1, 2), (-2,-4)

-1 is only connected to 2, but that does't help as  -2 is connected to -4 and 4 both. Thus, it doesn't represent a function.

  • Case 4: (-2, 4), (-1, 2), (-1, -2), (-2,-4)

-2 is connected to 4 and -4, and -1 is connected to 4 and -4, so its not a function.

Thus, the set of ordered pairs from listed options demonstrating a function is given by: Option A: (-2,-4), (-1, -2), (1, 2), (2, 4)

Learn more about functions here:

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