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what is the vertex of the quadratic function below y=1/2 x^2 +x+3

Sagot :

Answer: the vertex is 1,7/2

Step-by-step explanation: this is the answer because first you label the first one a the second one b and the last one c then if you find the axis of symmetry by doing [tex]\frac{-b}{2(a)\\}[/tex] you will have your x for the vertex then plug in your x into the equation where ever there is a x tat where you plug it in then you will have the right answer... I hoped this help

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