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Find the value of x. Round to the nearest tenth (one decimal place)
19
21

Find The Value Of X Round To The Nearest Tenth One Decimal Place 19 21 class=

Sagot :

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Using the Pythagorean theorem:

X = sqrt(21^2 - 19^2)

X = sqrt(441 - 361)

X = sqrt(80)

X = 8.944

Rounded to the nearest tenth = 8.9

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Answer:

x = ~8.9

Step-by-step explanation:

a^2 + b^2 = c^2

c is the long side

a and b are the other two shorter sides

this means

x^2 + 19^2 = 21^2

x^2 + 361 = 441

x^2 = 441- 361

x^2 = 441- 361

x^2 = 80

square root of 80 = ~8.9

x = ~8.9

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