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CH4 + 2O + CO2 + 2 H2O
If 9.65 mole of methane reacts with oxygen to produce carbon dioxide and water, what mass of water is produced?

Sagot :

Answer:

347.4 (19.3 mole)

Explanation:

CH4 + 2O2 = CO2 + 2H2O

1(mole) - 9.65(mole)

2(mole) - x ⇒x = 9.65*2=19.3

m=n*M ⇒ m= 19.3*(1*2+16)= 19.3*18=347.4(g)

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