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Sagot :
The centripetal acceleration of the bucket at the bottom of the circular loop is 36 m/s².
The net force at the bottom of the circular loop is 68.7 N.
The given parameters:
- Mass of the bucket, m = 1.5 kg
- Radius of the circle, r = 1 m
- Speed of the bucket at bottom, v = 6 m/s
What is centripetal acceleration?
- Centripetal acceleration is the radial acceleration of an object in a circular path.
The centripetal acceleration of the bucket at the bottom of the circular loop is calculated as follows;
[tex]a_c = \frac{v^2}{r} \\\\a_c = \frac{6^2}{1} \\\\a_c = 36 \ m/s^2[/tex]
The net force at the bottom of the circular loop is calculated as follows;
[tex]F_{net} = m(g + a_c)\\\\F_{net} = 1.5(9.8 + 36)\\\\F_{net} = 68.7 \ N[/tex]
Learn more about centripetal acceleration here: https://brainly.com/question/79801
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