Answered

Join IDNLearn.com today and start getting the answers you've been searching for. Our platform offers comprehensive and accurate responses to help you make informed decisions on any topic.

A gas has an initial pressure of 2065 mmHg and temperature of 416 K. What is
the new pressure in atm if the temperature is cooled to 382 K?

Sagot :

Answer:

1896 mmHg

Explanation:

P1/T1 = P2/T2

P1 = 2065 mmHg

T1 = 416 K

P2 = ?

T2 = 382 K

Solve for P2 --> P2 = P1T2/T1

P2 = (2065 mmHg)(382 K) / (416 K) = 1896 mmHg

Thank you for using this platform to share and learn. Don't hesitate to keep asking and answering. We value every contribution you make. Your questions find clarity at IDNLearn.com. Thanks for stopping by, and come back for more dependable solutions.