Join IDNLearn.com and become part of a knowledge-sharing community that thrives on curiosity. Find the answers you need quickly and accurately with help from our knowledgeable and dedicated community members.
Sagot :
Answer:
The ordered pairs of [tex]p(x) = x^{2}-2\cdot x -35[/tex] are [tex](r_{1}, p(r_{1})) = (-5, 0)[/tex] and [tex](r_{2},p(r_{2})) = (7,0)[/tex], respectively.
Step-by-step explanation:
Let be [tex]p(x)[/tex] a quadratic expression whose two real zeros are real, a value of [tex]x[/tex] is a zero of the expression when [tex]p(x) = 0[/tex]. The factored form of the expression is represented by [tex]p(x) = (x-r_{1})\cdot (x-r_{2})[/tex], where [tex]r_{1}[/tex] and [tex]r_{2}[/tex] are the zeroes of the polynomial.
If [tex]p(x) = x^{2}-2\cdot x -35[/tex], then the ordered pairs that represent the zeros are:
[tex](r_{1}, p(r_{1})) = (-5, 0)[/tex] and [tex](r_{2},p(r_{2})) = (7,0)[/tex]
Quadratic equation has a leading coefficient of the second degree. The ordered pairs of the quadratic equation are (-5,0) and (7,0).
What is a quadratic equation?
A quadratic equation is an equation whose leading coefficient is of second degree also the equation has only one unknown while it has 3 unknown numbers.
It is written in the form of ax²+bx+c.
As the factors of the quadratic equation are given, therefore, equating the factors with zero in order to get the value of x.
[tex](x+5)=0\\x = -5[/tex]
[tex](x-7)=0\\x = 7[/tex]
Now, if we see the quadratic equation or the function it is written as,
[tex]y = x^2-2x-35 \\\\ x^2-2x-35 = 0[/tex]
Therefore, the value of y is 0.
Thus, the ordered pairs of the quadratic equation are (-5,0) and (7,0).
Learn more about Quadratic Equation:
https://brainly.com/question/2263981
We appreciate your participation in this forum. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. Thank you for choosing IDNLearn.com. We’re committed to providing accurate answers, so visit us again soon.
