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Give the o.N. Of each of the elements magnesium and oxygen in the reactants and in the products 2Mg + O2=2MgO

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Answer:

[tex]2Mg^0 + O_2^0\rightarrow2Mg^{2+}O^{2-}[/tex]

Explanation:

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In this case, according to the rules for the oxidation states in chemical reactions, it is possible to realize that lone elements have 0 and since magnesium is in group 2A, it forms the cation Mg⁺² as it loses electrons and oxygen is in group 6A so it forms the anion O⁻²; therefore resulting oxidation numbers are:

[tex]2Mg^0 + O_2^0\rightarrow2Mg^{2+}O^{2-}[/tex]

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