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Sagot :
Answer:
14.91 mL
Explanation:
Assuming the weak acid is monoprotic, we can solve this problem using the equation:
- C₁V₁=C₂V₂
Where subscript 1 stands for the Volume and Concentration of the weak acid, while 2 stands for those of NaOH.
We input the data:
- 25.00 mL * 0.1084 M = 0.1817 M * V₂
And solve for V₂:
- V₂ = 14.91 mL
The volume of 0.1817 M NaOH has to be added to reach the equivalence point is 14.91 mL.
How we calculate the volume?
Volume for the given solution will be calculated from the below equation:
M₁V₁ = M₂V₂, where
M₁ = Molarity of weak acid = 0.1084 M
V₁ = volume of weak acid = 25 mL
M₂ = molarity of NaOH = 0.1817 M
V₂ = volume of NaOH = to find?
On putting all these values on the above equation and calculate for V₂ as:
V₂ = (0.1084)(25) / (0.1817) = 14.91 mL
Hence required volume is 14.91 mL.
To know more about molarity, visit the below link:
https://brainly.com/question/489225
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