Answered

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A 21.5 L sample of gas at 107 kPa has a temperature of 27.2 °C. What is the pressure of the gas
if it is transferred to a 32.6L container at 44.1 °C?

Sagot :

Cricetusidn

Answer:

The right answer is "74.516 kPa".

Explanation:

The given values are:

V₁ = 21.5 L

V₂ = 32.6L

P₁ = 107 kPa

T₁ =27.2°C+273

T₂ = 44.1 °C+273

As we know,

⇒  [tex]\frac{P_1V_1}{T_1}= \frac{P_2V_2}{T_2}[/tex]

then,

⇒  [tex]P_2=\frac{P_1V_1T_2}{T_1V_2}[/tex]

On substituting the given values, we get

⇒       [tex]=\frac{107\times 21.5\times (44.1+273)}{(27.2+273)\times 32.6}[/tex]

⇒       [tex]=\frac{107\times 21.5\times 317}{300.2\times 32.6}[/tex]

⇒       [tex]=\frac{729258.5}{9786.52}[/tex]

⇒       [tex]=74.516 \ kPa[/tex]

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