Answer: We must use 5 moles of [tex]Fe_2O_3[/tex]
8.19 moles of oxygen are needed
Explanation:
The balanced chemical reaction is:
[tex]Fe_2O_3(s)+3CO(g)\rightarrow 2Fe(l)+3CO_2(g)[/tex]
As is the limiting reagent as it limits the formation of product and is the excess reagent.
According to stoichiometry :
2 moles of require = 1 mole of
Thus 10 moles of [tex]Fe[/tex] will require=[tex]\frac{1}{2}\times 10=5moles[/tex] of [tex]Fe_2O_3[/tex]
Thus we must use 5 moles of [tex]Fe_2O_3[/tex]
The balanced chemical reaction is:
According to stoichiometry :
2 moles of require = 3 mole of [tex]O_2[/tex]
Thus 5.46 moles of [tex]Fe_2O_3[/tex] will require=[tex]\frac{3}{2}\times 5.46=8.19moles[/tex]
8.19 moles of oxygen are needed
