Step-by-step explanation:
✧ [tex] \underline{ \underline{ \large{ \tt{S \: O \: L \: U \: T \: I \: O \: N}}} }: [/tex]
- Set up an equation and solve for x :
⋆ [tex] \large{ \bf{(4x + 9) \degree = 2x \degree + (3x - 12) \degree}} [/tex] [ Exterior angle is always equal to the sum of two non - adjacent interior angles ]
~Remove the unnecessary brackets
⟶ [tex] \large{ \bf{4x \degree + 9 \degree = 2x \degree + 3x \degree - 12 \degree}}[/tex]
~Add the like terms : 2x ° & 3x°
⟶ [tex] \large{ \bf{4x \degree + 9 \degree = 5x \degree - 12 \degree}}[/tex]
~Move 4x to right hand side and change it's sign
~Similarly move 12 to left hand side and change it's sign
⟶ [tex] \large{ \bf{9 \degree + 12 \degree = 5x \degree - 4x \degree}}[/tex]
⟶ [tex] \large{ \bf{21 \degree = x \degree}}[/tex]
⟶ [tex]{ \large{ \bf{x = 21 \degree}}}[/tex]
- Now , Substituting the value of x in (4x+9)° [ Exterior angle ]
⤿ [tex] \large{ \bf{4 \times 21 \degree + 9 \degree}} = \boxed{93 \degree}[/tex]
☥ [tex] \boxed{ \boxed{ \large{ \tt{Our \: Final \: Answer : \boxed{ \underline { \tt{93\degree}}}}}}}[/tex]
Hope I helped ! ツ
Have a wonderful day / night ! ♡
❅ Let me know if you have any questions regarding my answer! ❅
☞ [tex] \underline{ \underline{ \mathfrak{Carry \: On \: Learning}}}[/tex] !! ✎
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