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|x+3|, if x>5
I really need help were supposed to be using the absolute value!! If you can add an explanation that would be great!!

Sagot :

DWReadidn

Answer:

Step-by-step explanation:

Suppose x+3 < 0. Subtract 3 from both sides of the inequality.

x < -3

So, x+3 is negative when x < -3. When x>5,

x+3 > 8, which is positive, so the absolute value function has no effect.

|x+3| > 8

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