Answer:
{-8, -4}
Step-by-step explanation:
Rewrite this function y=x2 +12x +32 as y = x^2 + 12x + 32; " ^ " indicates exponentiation.
Set this x^2 + 12x + 32 equal to zero (to find the zeros):
x^2 + 12x + 32 = 0. Let's solve this using the quadratic formula, which applies when ax^2 + bx + c = 0:
-b ± √(b^2 - 4·a·c)
x = -------------------------------
2a
The coefficients of the given quadratic are {1, 12, 32}. Thus, the discriminant is
b^2 - 4ac, or 12^2 - 4(1)(32), or 144 - 128, or 16. Therefore, we have:
-12 ± √16 -12 ± 4
x = -------------------- which simplifies to: x = --------------- = { -8, -4}
2 2
The zeros are {-8, -4}
