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Sagot :
Answer:
[tex]6.42\ \text{m/s}[/tex]
Explanation:
v = Final velocity
u = Initial velocity = 0
s = Displacement of Tarzan's feet = 2.1 m
a = g = Acceleration due to gravity = [tex]9.81\ \text{m/s}^2[/tex]
From the kinematic equations we get
[tex]v^2-u^2=2as\\\Rightarrow v=\sqrt{2as+u^2}\\\Rightarrow v=\sqrt{2\times 9.81\times 2.1+0}\\\Rightarrow v=6.42\ \text{m/s}[/tex]
At the instant just before Tarzan's feet touch the ground the velocity of his feet are [tex]6.42\ \text{m/s}[/tex].
The speed at an instant just before Tarzen's feet touch the ground will be
[tex]V=6.42\ \dfrac{m}{s}[/tex]
What is speed?
The speed of any body is defined as the movement of the body with respect to the time.
It is given in the question that
Mass of the Tarzen m=100 kg
The distance of the Tarzen's feet from the ground s=2.1 m
The acceleration due to gravity [tex]a=9.81\ \frac{m}{s^2}[/tex]
The speed of the Tarzen will be calculated by applying the equation of motion.
[tex]v^2=u^2+2as[/tex]
Since initial velocity is zero u=0
[tex]v^2=2as[/tex]
[tex]v=\sqrt{2as}[/tex]
[tex]v=\sqrt{2\times 9.81\times 2.1} =6.42 \ \frac{m}{s}[/tex]
Thus the speed at an instant just before Tarzen's feet touch the ground will be
[tex]V=6.42\ \dfrac{m}{s}[/tex]
To know more about speed follow
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