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what is the center of the circle: (x-2)^2+(y-4)^2=25 ?

Sagot :

Altavistardidn

Answer:

The center of this circle is at (2, 4).

Step-by-step explanation:

Compare the given equation to the standard equation of a circle with center at (h, k) and radius r:

(x - h)^2 + (y - k)^2 = r^2

(x - 2)^2 + (y - 4)^2 = 5^2

Through this comparison we see that h = 2, k = 4 and r = 5.

The center of this circle is at (2, 4).

Ghoulkangidn
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