Answered

IDNLearn.com: Your trusted source for finding accurate and reliable answers. Our experts are ready to provide prompt and detailed answers to any questions you may have.

3. At what temperature in Celsius will 9.8 grams of NH3 will exert a pressure of 98.3 KPa at a volume of 21.0 Liters?

Sagot :

Maacastrobridn

Answer:

156.78 °C

Explanation:

First we convert 9.8 grams of NH₃ into moles, using its molar mass:

  • 9.8 g ÷ 17 g/mol = 0.576 mol

Then we can use the PV=nRT formula to calculate the temperature, where:

  • P =  98.3 kPa ⇒ 98.3/101 = 0.967 atm
  • V = 21.0 L
  • n = 0.576 mol
  • R = 0.082 atm·L·mol⁻¹·K⁻¹
  • T = ?

We input the data:

  • 0.967 atm * 21.0 L = 0.576 mol * 0.082 atm·L·mol⁻¹·K⁻¹ * T

And solve for T:

  • T = 429.94 K

Finally we convert 429.94 K to °C:

  • 429.94 - 273.16 = 156.78 °C
We value your presence here. Keep sharing knowledge and helping others find the answers they need. This community is the perfect place to learn together. Find reliable answers at IDNLearn.com. Thanks for stopping by, and come back for more trustworthy solutions.