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A sample of hydrogen takes up 34.0 dm3 of space when it is under 500.0 kPa of pressure. When the pressure is changed to 340.0 kPa, what is the new volume? dm3 H2

Sagot :

Maacastrobridn

Answer:

50 dm³

Explanation:

Assuming constant temperature, we can solve this problem using Boyle's law, which states:

  • P₁V₁=P₂V₂

Where in this case:

  • P₁ = 500.0 kPa
  • V₁ = 34.0 dm³
  • P₂ = 340.0 kPa
  • V₂ = ?

We input the data:

  • 500.0 kPa * 34.0 dm³ = 340.0 kPa * V₂

And solve for V₂:

  • V₂ = 50.0 dm³

Thus the answer is 50.0 dm³ H₂.