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Find the 14th term of the geometric sequence 2,6,18, ...

Sagot :

Answer:

Step-by-step explanation:

The answer to this question link is here

https://socratic.org/answers/623991

Hellomialaidn

The geometric sequence is starting with 2 and multiplying by 3 every time. We can get the rule of this sequence by...

  • If 2 is [tex]a_{1}[/tex], 6 is [tex]a_{2}[/tex], 18 is [tex]a_{3}[/tex], etc...
  • then, [tex]a_{n}[/tex]=2(3)^(n - 1)

For the 14th term, plus in 14 for n, and it will look like this:

= 2(3)^(14 -1)

= 2(3)^(13)

= 3188646

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