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Sagot :
Answer:
2√3 = hypotenuse
√3 = side
Step-by-step explanation:
[tex]\sqrt{3^{2} +x^{2} } = 2x \\\sqrt{9 +x^{2} } = 2x\\9+x^{2} =(2x)^{2} \\9+x^{2} = 4x^{2} \\9 = 4x^{2} - x^{2} = 3x^{2} \\3 = x^{2}\\\sqrt{3} = x\\\\2x = 2\sqrt{3}\\[/tex]
Answer:
the smaller side=√3
hypotenuse=2√3
Step-by-step explanation:
(see the attachment below)

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