Find solutions to your problems with the expert advice available on IDNLearn.com. Discover comprehensive answers to your questions from our community of experienced professionals.
Sagot :
Answer:
Step-by-step explanation:
3x²+3x-6
=3(x²+x-2)
=3(x²+2x-x-2)
=3[x(x+2)-1(x+2)]
=3(x+2)(x-1)
Answer:
3(x - 1)(x + 2)
Step-by-step explanation:
Factor 3x^2 + 3x - 6
Step 1: Factor out a common factor from all terms if possible.
All terms have a common factor of 3. We start by factoring out the 3.
3x^2 + 3x - 6 =
= 3(x^2 + x - 2)
Step 2: We now need to deal with factoring x^2 + x - 2.
It is a trinomial of the form x^2 + ax + b, where the coefficient of x^2 is 1. To factor it, we need 2 numbers whose product is b and whose sum is a. In our case, we have x^2 + x - 2. We need two numbers whose product is -2 and whose sum is 1.
Pairs of numbers with product -2:
-2 and 1 since -2 * 1 = -2
-1 and 2 since -1 * 2 = -2
Now we add the two numbers in each line above.
-2 + 1 = -1 The sum is -1, but we need a sum of 1, so this is not it.
-1 + 2 = 1 Here we do get the sum of 1 that we need, so this pair of numbers is what we need.
The two numbers we need for factoring are -1 and 2.
Now we start the next step.
The factored trinomial will have this form.
= 3(x )(x )
All we need to do now is place each of the numbers in one of the blanks.
= 3(x - 1)(x + 2)
Answer: 3(x - 1)(x + 2)
Thank you for joining our conversation. Don't hesitate to return anytime to find answers to your questions. Let's continue sharing knowledge and experiences! Thank you for trusting IDNLearn.com with your questions. Visit us again for clear, concise, and accurate answers.