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Sagot :
Answer:
26
Step-by-step explanation:
JKL= ABC, jkl=abc
1.) use law of sines to find k.
[tex]c^{2} =a^{2} +b^{2} -2abCosC[/tex]
[tex]c=\sqrt{920^{2} +860^{2} -2(920)(860)cos(126) } = 1586.225515[/tex]
2.) use law of cosines to find L
[tex]\frac{a}{sinA} =\frac{b}{sinB} =\frac{c}{sinC}[/tex]
plug in for b and c: [tex]\frac{860}{sinB} =\frac{1586.225515}{sin126}[/tex]
cross multiply: [tex]\frac{1586.23sinB}{1586.23} =\frac{860sin126}{1586.23}[/tex]
[tex]sinB= 0.4386227612\\B=sin^-1(0.4386227612)= 26.01604086\\[/tex]
L=26
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