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what is the mass of 1.24 x 10^23 molecules of N2O2

Sagot :

Spaceidn

Answer:

12.4 g N₂O₂

General Formulas and Concepts:

Chemistry

Atomic Structure

  • Reading a Periodic Table
  • Moles
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Stoichiometry

  • Using Dimensional Analysis

Explanation:

Step 1: Define

[Given] 1.24 × 10²³ molecules N₂O₂

[Solve] grams N₂O₂

Step 2: Identify Conversions

Avogadro's Number

[PT] Molar Mass of N - 14.01 g/mol

[PT] Molar Mass of O - 16.00 g/mol

Molar Mass of N₂O₂ - 2(14.01) + 2(16.00) = 60.02 g/mol

Step 3: Convert

  1. [DA] Set up:                                                                                                        [tex]\displaystyle 1.24 \cdot 10^{23} \ molecules \ N_2O_2(\frac{1 \ mol \ N_2O_2}{6.022 \cdot 10^{23} \ molecules \ N_2O_2})(\frac{60.02 \ g \ N_2O_2}{1 \ mol \ N_2O_2})[/tex]
  2. [DA] Divide/Multiply [Cancel out units]:                                                          [tex]\displaystyle 12.3588 \ g \ N_2O_2[/tex]

Step 4: Check

Follow sig fig rules and round. We are given 3 sig figs.

12.3588 g N₂O₂ ≈ 12.4 g N₂O₂

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