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The 6kg box is pushed to the left at a constant speed. The coefficient of friction is 0.78. Solve for the amount of force with which the hand pushes the box. I think the answer is 45.8 n, but is it right?

Sagot :

Sphamandlachristinaidn

Answer:

45,86N

Explanation:

Fk=Uk×N

=0,78×6×9.8

=45,86N

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