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The head scale of a screw gauge contains 100 divisions and it's pitch is 1mm. what is the least count of the screw gauge​

Sagot :

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Answer:

0.01 mm

Explanation:

The least count of the screw gauge = pitch/number of divisions on circular scale

Pitch = 1 mm and number of divisions = 100

Substituting the values of the variables into the equation, we have

least count of the screw gauge = pitch/number of divisions on circular scale =  1 mm/100 = 0.01 mm

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