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Sagot :

Answer:

sinθ = [tex]\frac{2}{3}[/tex]

Step-by-step explanation:

Using the Pythagorean identity

sin²θ + cos²θ = 1 , then

sin²θ + ([tex]\frac{\sqrt{5} }{3}[/tex] )² = 1

sin²θ + [tex]\frac{5}{9}[/tex] = 1

sin²θ = 1 - [tex]\frac{5}{9}[/tex] = [tex]\frac{4}{9}[/tex] ( take the square root of both sides )

sinθ = [tex]\sqrt{\frac{4}{9} }[/tex] = [tex]\frac{2}{3}[/tex]

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